Respuesta :

Answer:

t = 1

Step-by-step explanation:

the greatest velocity could be reached:

v' = 0

12 - 12t =0

or 12t =12

t = 12/12

t = 1

v=12t-6t^2

Find derivative of v

[tex]\\ \sf\longmapsto \dfrac{dv}{dx}[/tex]

[tex]\\ \sf\longmapsto \dfrac{d}{dx}12t-6t^2[/tex]

[tex]\boxed{\sf \dfrac{d(x^n)}{dx}=nx^{n-1}}[/tex]

[tex]\\ \sf\longmapsto 12-12t[/tex]

Let it be 0

[tex]\\ \sf\longmapsto 12-12t=0[/tex]

[tex]\\ \sf\longmapsto 12=12t[/tex]

[tex]\\ \sf\longmapsto t=\dfrac{12}{12}[/tex]

[tex]\\ \sf\longmapsto t=1s[/tex]