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In this sample we can see that typical males weigh more than typical females. Show that this is true by calculating the typical interval for each group using mean ±ADM.

Type in a number only. For example, 26.2 not 26.2kg.

Typical males weigh between _
and _

Typical females weigh between _
and _

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fichoh

The required interval values are :

  • Male interval : 69.5 ≤ mean ≤ 86.9
  • Male interval : 69.5 ≤ mean ≤ 86.9Female interval : 52.6 ≤ mean ≤ 68.6

Given that :

Male :

Mean = 78.2 ; ADM = 8.7

Female :

Mean = 60.6 ; ADM = 8.0

The interval is calculated thus :  mean ± ADM

INTERVAL FOR MALE :

male mean value ± ADM

78.2 ± 8.7

Lower boundary = 78.2 - 8.7 = 69.5

Upper boundary = 78.2 + 8.7 = 86.9

INTERVAL FOR FEMALE :

Female mean value ± ADM

60.6 ± 8.0

Lower boundary = 60.6 - 8.0 = 52.6

Upper boundary = 60.6 + 8.0 = 68.6

Hence,

Male interval : 69.5 ≤ mean ≤ 86.9

Female interval : 52.6 ≤ mean ≤ 68.6

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