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PLEASE HELP. MULTIPLE CHOICE ONE QUESTION! write the equation that is perpendicular to the given line and passes through the given point Y-4=5/4 (x+3); (-7 8)

y-8=-2/5 (x-7)
y-8=2/5 (x-7)
y-8=-2/5 (x+7)
y-8=2/5 (x+7)

Respuesta :

texaschic101
y - 4 = 5/2(x + 3)...slope here is 5/2. A perpendicular line will have a negative reciprocal slope. So our perpendicular line will have a slope of -2/5

y - y1 = m(x - x1)
slope(m) = -2/5
(-7,8)...x1 = -7 and y1 = 8
now we sub
y - 8 = -2/5(x - (-7) =
y - 8 = -2/5(x + 7) <===