Respuesta :
For the rate of change of Function 1, it is 2 because when I did delta y over delta x (3/-1)-(5/-2) i got negative 2 over negative 1. Two negatives equal a positive. For the rate of change of Function 2, it is 4. I picked two points that can even meet. Then I use the formula of rise over run to comes out as 4/1 simplified to 4. So Function 2 has the greater rate of change.
Answer:
The rate of change of first function is -2.
The rate of change of second function is 4.
Function 2 has greater rate of change.
Step-by-step explanation:
If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the formula for rate of change is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
From the table and graph consider any two points to find the rate of change of each function.
From the table, let as consider two point (-1,3) and (-2,5). The rate of change of first function is
[tex]m=\frac{5-3}{-2-(-1)}[/tex]
[tex]m=\frac{2}{-2+1}[/tex]
[tex]m=-2[/tex]
The rate of change of first function is -2.
From the graph, let as consider two point (-1,0) and (0,4). The rate of change of second function is
[tex]m=\frac{4-0}{0-(-1)}[/tex]
[tex]m=\frac{4}{1}[/tex]
[tex]m=4[/tex]
The rate of change of second function is 4.
Since -2<4, therefore function 2 has greater rate of change.