9514 1404 393
Answer:
8/15
Step-by-step explanation:
The probability of 1 white counter in the two draws is ...
p(1 white) = p(1st white & 2nd not) +p(1st not & 2nd white)
= (6/10)(4/9) +(4/10)(6/9) = (24+24)/90 = 8/15
The probability that only one of the counters is white is 8/15.
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Alternate solution
There are 10C2 = 45 ways to draw 2 counters. Of these, there are 6C2 = 15 ways to draw 2 white counters, 4C2 = 6 ways to draw 2 non-white counters, and (6C1)(4C1) = 24 ways to draw 1 white counter. The probability of drawing 1 white counter in the two draws is 24/45 = 8/15.
