mchonemiles2008
contestada

The rectangle shown has a
perimeter of 70 cm and the given
area. Its length is 5 more than
twice its width. Write and solve a
system of equations to find the

*giving brainiest answer, easy 50 points

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SweetyShahastra

Answer:

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Answer:

Stewidth of the rectangle = b = x

length of the rectangle = l = 8 + 2x

Perimeter of the rectangle = 70cm

Also, perimeter of the rectangle = 2(l + b)

70 = 2[x + (8 + 2x)]

70 = 2(x + 8 + 2x)

70 = 2(3x + 8)

70 = 6x + 16

70 - 16 = 6x

54 = 6x

54/6 = x

9 = x

Therefore, b = x

b = 9cm

l = 8 + 2x

I = 8 + 2×9

I = 8 + 18

I = 26cm

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