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Suraj took a slice of pizza from the freezer and put it in the oven. The pizza was heated at a constant rate.
The table compares the pizza's temperature (in degrees Celsius) and the time since Suraj started heating it (in minutes).
Time (minutes) Temperature (degrees Celsius)
111 2.52.52, point, 5
777 47.547.547, point, 5
131313 92.592.592, point, 5
How fast was the pizza heated?

Respuesta :

For this case, the first thing we should do is write the linear function that best suits the table.

In this case we have the following function:

y = 7.5x - 5

C = 7.5t-5

For C = 100 we have:

100 = 7.5t-5

We clear the time:

t = (100 + 5) / (7.5)

t = 14

it did take the pizza to reach 100 degrees Celsius about 14 minutes.

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