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In the graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded and labeled B, and the area where f(x) and g(x) have shading in common is labeled AB.

Graph of two intersecting lines. The line f of x is solid and goes through the points 0, 4, and 4, 0 and is shaded below the line. The other line g of x is solid, and goes through the points 0, negative 1 and 2, 5 and is shaded below the line.

The graph represents which system of inequalities?

y ≤ −3x − 1
y ≤ −x − 4

y > −3x + 1
y ≤ −x − 4

y < 3x − 1
y ≤ −x + 4

y ≤ 3x − 1
y ≥ −x + 4

In the graph the area below fx is shaded and labeled A the area below gx is shaded and labeled B and the area where fx and gx have shading in common is labeled class=

Respuesta :

IIitzAryanII

Answer:

Answer:

y ≤ 3x − 1, y ≤ −x + 4

Step-by-step explanation:

The line f(x) is solid and goes through the points (0, 4) and (4, 0) and is shaded below the line.

The line that satisfies the point (0,4) and (4,0) is y=-x+4

Since it is shaded below the line, we have the inequality sign:

Therefore, one of the lines is:

[tex]y\leq -x+4[/tex]

The line g(x) is solid and goes through the points (0, -1) and (2, 5) and is shaded below the line.

Slope,

[tex]m=\frac{5-(-1)}{2-0}=3[/tex]

When x=0, y=-1

y=mx+b

y=3x+b

-1=3(0)+bb=-1

Therefore, the equation of the line is:

y=3x-1

Since it is shaded below the line, we have the inequality sign: [tex]\leq[/tex]

Therefore, the other line is:

[tex]y\leq 3x-1[/tex]

Ver imagen IIitzAryanII
rileyramroop45

Answer:

y ≤ 3x − 1, y ≤ −x + 4

Step-by-step explanation:

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