Given:-
[tex]\red{➤}\:[/tex][tex]\sf f(x) = 2x^3-5x^2-3x [/tex]
[tex]\red{➤}\:[/tex][tex]\sf g(x)=x[/tex]
[tex]\\[/tex]
To Find:-
[tex]\orange{☛}\:[/tex][tex]\sf h(x) [/tex]
[tex]\\[/tex]
Solution:-
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf h(x) =f(x)÷g(x) \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{f(x)}{g(x)}= \dfrac{2x^3-5x^2-3x}{x} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{x(2x^2-5x-3)}{x} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf 2x^2-5x-3 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf{h(x)= 2x^2-5x-3}} \\\end{gathered} [/tex]
