Respuesta :
Explanation:
The power P dissipated by a heater is defined as
[tex]P = VI[/tex]
where V is the voltage and I is the current.
a) The current running through a 130-W heater is
[tex]I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}[/tex]
b) The resistance R of the heater is
[tex]P = VI = (IR)I = I^2R[/tex]
where [tex]V= IR[/tex] is our familiar Ohm's Law.
[tex]\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}[/tex]
[tex]R = 110.8\:Ω[/tex]
The current running through the heater when it is operating is 1.08 A.
The resistance of the heater is 110.8 ohm.
What is current?
- A current is a flow of Charges.
- The formula of current is , current I = power P / voltage V
- The SI unit of current is ampere A.
So, from the above equation we can calculate,
current I = P/V
∴ I = 130 / 120
∴ I = 1.08 A
What is resistance?
- The resistance is a quantity which oppose the current flow in a circuit.
- The formula of resistance is ( in the terms of power P and ohm's law V=IR ) resistance R = P/I^2.
- The SI unit of resistance is ohm.
So, from the equation we can calculate,
Resistance R = P/I^2
∴ R = 130/(1.08)^2
∴ R = 110.8 ohm
Thus, the current running through the heater when it is operating is 1.08 A.
The resistance of the heater is 110.8 ohm.
Learn more about resistance and resistivity here -
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