The height to which the rock can attain is 7.6 m
From the question given above, the following data were obtained:
Initial velocity (u) = 12.2 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
The maximum height to which the rock can attain can be obtained as follow:
v² = u² – 2gh (since the rock is going against gravity)
0² = 12.2² – (2 × 9.8 × h)
0 = 148.84 – 19.6h
Collect like terms
0 – 148.84 = – 19.6h
–148.84 = –19.6h
Divide both side by –19.6
h = –148.84 / –19.6
Thus, the height to which the rock can attain is 7.6 m
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