Applying the midsegment theorem, the value of x = 5
Recall:
Thus:
DE = 1/2(AC)
2x - 3 = 1/2(x + 9)
2(2x - 3) = x + 9
4x - 6 = x + 9
4x - x = 6 + 9
3x = 15
x = 5
Therefore, applying the midsegment theorem, the value of x = 5
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