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For each of the following amounts, calculate the mass
of the sample:
a) 5.32 mol barium iodide, Balz
b) 17.8 mol sulfur dioxide, SO2
c) 1.25 mol AspirinTM, CHO4
d) 0.234 mol magnesium nitrite, Mg(NO2)2

Respuesta :

The masses of the following amount of compound are as follows:

a. 2080.12 grams of barium iodide

b.1139.2 grams of sulphur dioxide

c. 96.25 grams of AspirinTM

d. 27.144 grams of magnesium nitrite

The molarity formula is represented as follows;

molarity = mass / molar mass

Recall we are ask to find the masses of the compounds. Therefore,

  • mass = molarity × molar mass

Mass of BaI₂

a 5.32 mol barium iodide, BaI₂

molarity = 5.32 mol

molar mass of  BaI₂ = 137 + 127(2) = 137 + 254 = 391 g/mol

mass = 5.32 × 391 = 2080.12 grams.

Mass of SO₂

b. ) 17.8 mol sulphur dioxide, SO₂

molarity = 17.8 mol

molar mass of SO₂  = 32 + 32 = 64 g /mol

mass = 17.8 × 64 = 1139.2 grams.

Mass of CHO₄

c. 1.25 mol AspirinTM, CHO₄

molarity = 1.25 mol

molar mass of  CHO₄ = 12 + 1 + 64 = 77 g / mol

mass = 1.25 × 77 = 96.25 grams

Mass of Mg(NO₂)₂

d. 0.234 mol magnesium nitrite, Mg(NO₂)₂

molarity = 0.234 mol

molar mass = 24 + 14(2) + 32(2) = 24 + 28 + 64 = 116 g/mol

mass = 116 × 0.234 = 27.144 grams.  

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