Respuesta :
Answer:
B and C are both correct
Step-by-step explanation:
18/6 = 3
h¹⁰/h¹² = h⁽¹⁰⁻¹²⁾ = h⁻² = 1/h²
the a⁻⁴ term remains unchanged and = 1/a⁴
3a⁻⁴h⁻² = [tex]\frac{3}{a^4h^2}[/tex]
Answer:
B and C are both correct
Step-by-step explanation:
18/6 = 3
h¹⁰/h¹² = h⁽¹⁰⁻¹²⁾ = h⁻² = 1/h²
the a⁻⁴ term remains unchanged and = 1/a⁴
3a⁻⁴h⁻² = [tex]\frac{3}{a^4h^2}[/tex]