Respuesta :

DynamoPrince2612

Step-by-step explanation:

Simply Equation 1

R. H. S

6x^2 -x +3-2x^2-8

==> 6x^2-2x^2 -x +3-8

==> 4x^2-x-5 .....(1)

Simply equation 2

L. H. S

4x^2+2x-5-3x

==> 4x^2 +2x-3x-5

==> 4x^2-x-5 ....(2)

Since here, RHS = LHS

both eqn (1) = eqn(2)

hence they are equal.

Answer:

yes they are equal

Step-by-step explanation:

for the equation [tex]4x^{2} +2x-5-3x[/tex] you're going to collect like terms

2x-3x=5x

so your final equation is [tex]4x^{2} -x-5[/tex]

for the equation [tex]6x^{2} -x+3-2x^{2} -8[/tex] you're going to collect like terms

[tex]6x^{2} -2x^{2} =4x^{2}[/tex]

then you're going to calculate the difference

3x-8=-5

so your final equation is [tex]4x^{2} -x-5[/tex]

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