Answer:
M(AgNO3) = 169,8731 g mol
Explanation:
M(Ag) = 107,8682 g mol
M(N) = 14.0067 g mol
M(O) = 15.9994 g mol
M(AgNO3) = M(Ag) + M(N) + 3 x M(O) = 107.8682 + 14.0067 + 3 x 15.9994 =
= 169,8731 g mol
Just sum up all the respective elements' molar mass.