Answer:
1. log(x2 - 15) = log(2x) form 1 to 5
2. 10.00 ( log(x2 - 15) - log(2x) = 0 ⇒ log([tex]\frac{x^{2}-15 }{2x}[/tex]) = 0 ⇒ [tex]\frac{x^{2}-15}{2x}[/tex] = 10^0 )
3. x2 - 15 = 2x
4. x2 - 2x - 15 = 0
5. (x - 5)(x + 3) = 0
6. X-5 = 0 or x +3=0
7. Potential solutions are -3 and 5
