Respuesta :
Trapezium
parallel sides = 18 cm, 12cm
Height = 8cm
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Area of trapezium =
[tex] \frac{1}{2} \times (a + b) \times h[/tex]
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[tex] \frac{1}{2} \times (a + b) \times h[/tex]
[tex] \frac{1}{2} \times (18 + 12) \times 8[/tex]
[tex] \frac{1}{2} \times (30) \times 8[/tex]
[tex] \frac{1}{1} \times (15) \times8[/tex]
[tex]120 \: cm ^{2} [/tex]
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Therefore, Area of trapezium is [tex]120 \: cm {}^{2} [/tex]
Answer:
Area of Trapezium = 120 cm³
Step-by-step explanation:
Trapezium = 1/2 * (a+b) * h [Formulae]
A & b = Sum of parallel sides
Given that,
- Height H = 8
- Sum of parallel sides = 18 and 12, 18+12
Solved:
- 1/2(18+12)8 cm²
- 1/2 * 30 * 8 cm²
- 15 * 8 cm²
- 120 cm²
Therefore,the area of trapezium is 120 sq. cm or 120 cm².