Answer:
[tex]\sf (-\dfrac{4}{7} ,1\dfrac{4}{7} )[/tex]
given:
insert question 2 into 1
[tex]\sf -x + 1 = 6x + 5[/tex]
[tex]\sf -x - 6x = 5 - 1[/tex]
[tex]\sf -7x = 4[/tex]
[tex]\sf x = -\frac{4}{7}[/tex]
find the value of y:
[tex]\sf y = -x + 1[/tex]
[tex]\sf y = -\frac{-4}{7} + 1[/tex]
[tex]\sf y = \frac{4}{7} + 1[/tex]
[tex]\sf y = \frac{4}{7} +\frac{7}{7}[/tex]
[tex]\sf y = \frac{11}{7}[/tex]
[tex]\sf y = 1\frac{4}{7}[/tex]
Therefore coordinates: (x,y) = [tex]\sf (-\dfrac{4}{7} ,1\dfrac{4}{7} )[/tex]
