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The pressure on a volume of liquid V = 1.0 mº at the surface is approximately equal to the atmospheric pressure Patm = 1.00 x 105 N/m2. If this volume of liquid is now
placed at a depth where the pressure is P = 2.30 x 10' N/m², what will be the change in volume of the liquid (in mº)? The bulk modulus of the liquid is 8.0 x 100 N/m².
(Include the appropriate sign with your answer.)
m
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Respuesta :

Answer:-2.86*10⁻⁴

Explanation: Use the equation change in volume = (change in pressure * original volume) / Bulks Modulus. ΔV = (-Δp*V₀) / B

Plugging in your numbers, you should get ΔV = (-2.29*10⁷*1) / (8*10¹⁰) = -2.86*10⁻⁴

ΔP = P₂-P₁  ----> ΔP = 2.30*10⁷ - 1.00*10⁵ = 2.29*10⁷

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