Answer:
[tex]\sqrt{102} > 6\frac{1}{2} > \sqrt[\frac{1}{3}]{102} > \frac{69}{25}[/tex]
Step-by-step explanation:
[tex]4 < \sqrt[3]{102} < 5[/tex] [tex]\left\{\sqrt{64}=4,\sqrt[7]{125}=5\right\}[/tex]
[tex]6\frac{1}{2}=6.5[/tex]
[tex]\frac{69}{25}=2.76[/tex]
[tex]10 < \sqrt{102} < 11[/tex] [tex]\left\{\sqrt{100}=10\sqrt{121}=11\right\}[/tex]
So from greater to least:
[tex]\sqrt{102} > 6\frac{1}{2} > \sqrt[\frac{1}{3}]{102} > \frac{69}{25}[/tex]
I hope this helps you
:)
