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You stretch your arm and rotate around the center of yourself in the horizontal plane. Suppose you make 2 full revolutions every 1 second, and the distance from the center of your body to the tip of your finger is 1.2 m.
Find:
(a) Find the angular speed of your rotation
(b) Find the period of rotation.
(c) Find the speed of the tip of your finger

You stretch your arm and rotate around the center of yourself in the horizontal plane Suppose you make 2 full revolutions every 1 second and the distance from t class=

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onyebuchinnaji

(a) The angular speed of the rotation is 12.57 rad/s

(b) The period of the rotation is 0.5 s.

(c) The speed of the tip of your finger is 15.08 m/s.

Angular speed of the rotation

The angular speed of the rotation is calculated as follows;

ω = 2πN

where;

  • N is number of revolutions

ω = 2π x (2) = 4π  = 12.57 rad/s

Period of rotation

[tex]\omega = 2\pi f\\\\f = \frac{\omega}{2\pi} \\\\T = \frac{1}{f} = \frac{2\pi}{\omega} \\\\T = \frac{2\pi}{4\pi} = 0.5 \ s[/tex]

Speed of your finger

v = ωr

v = 12.57 x 1.2

v = 15.08 m/s

Learn more about angular speed here: https://brainly.com/question/6860269

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