Answer:
The specific heat of the sample unknown metal is approximately 0.45 J/g °C.
General Formulas and Concepts:
Thermodynamics
Specific Heat Formula: [tex]\displaystyle q = mc \triangle T[/tex]
- m is mass (g)
- c is specific heat capacity (J/g °C)
- ΔT is the change in temperature
Explanation:
Step 1: Define
Identify variables.
m = 112 g
ΔT = 20.0 °C
q = 1004 J
Step 2: Solve for c
- Substitute in variables [Specific Heat Formula]: [tex]\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})[/tex]
- Simplify: [tex]\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c[/tex]
- Isolate c: [tex]\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}[/tex]
- Round [Sig Figs]: [tex]\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}[/tex]
∴ specific heat capacity c is equal to around 0.45 J/g °C.
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Topic: AP Chemistry
Unit: Thermodynamics
