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TheAestheticBoy

Question :-

  • A Triangle has an Area of 48 cm² . The Height of the Triangle is 6 cm . What is the Base of the Triangle ?

Answer :-

  • Base of Triangle is 16 cm .

Explanation :-

As per the provided information in the given question, we have been given that the Area of Triangle is 48 cm² . It's Height is given as 6 cm . And, we have been asked to calculate the Base of Triangle .

For calculating the Base of Triangle , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Triangle} \: = \: \frac{1}{2} \: \times \: B \: \times \: H \: }} [/tex]

Where ,

  • B denotes to the Base .
  • H denotes to the Height .

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Area \: _{Triangle} \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: = \: \dfrac {1}{2} \: \times \: Base \: \times \: 6 } [/tex]

[tex] \longmapsto \: \: \: \sf {48 \: \times \: 2 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 1 \: \times \: Base \: \times \: 6} [/tex]

[tex] \longmapsto \: \: \: \sf {96 \: = \: 6 \: \times \: Base } [/tex]

[tex] \longmapsto \: \: \: \sf {Base \: = \: \dfrac {96}{6} } [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Base \: = \: 16 \: cm}} [/tex]

Hence :-

  • Base of Triangle = 16 cm .

[tex] \underline {\rule {180pt} {4pt}} [/tex]

TheAmethyst

Question : -

A triangle has an area of 48 square centimetres. The height of the triangle is 6 centimetres. What is the base of the triangle ?

Given : -

  • Area of triangle = 48 cm²

  • Height of triangle = 6 cm

To Find : -

  • Base of triangle

Formula Used : -

[tex] \blue{\boxed{Area \: of \: triangle = \frac{1}{2} \times b \times h}}[/tex]

Where ,

  • b = Base of triangle

  • h = Height of triangle

Concept : -

In this question the concept belongs to the areas of two dimensional shapes i.e. how we can find length , breadth or height with the help of given area .

So let's get started : -

[tex] \longmapsto \: 48 = \frac{1}{2} \times b \times 6[/tex]

Now , transposing 2 to left hand side :

[tex] \longmapsto \: 48 \times 2 = 1 \times b \times 6[/tex]

Now , multiplying 48 with 2 and multiplying b with 1 and 6 :

[tex] \longmapsto \: 96 = 6b[/tex]

Now , transposing 6 to left hand side :

[tex] \longmapsto \: \cancel\frac{96}{6} = b[/tex]

Now , by cancelling them we get :

[tex] \longmapsto \: \red{ \boxed{ \sf{b = 16 \: cm}}}[/tex]

  • Therefore , base of triangle is of 16 cm

Verifying : -

We know that area of triangle is equal to 48 cm². So :

[tex] \rightarrow \: \frac{1}{ \cancel2} \times \cancel{16} \times 6 = 48[/tex]

Now , by cancelling 16 with 2 we get :

[tex] \rightarrow \: 8 \times 6 = 48[/tex]

So , by multiplying we get :

[tex] \rightarrow \: 48 = 48[/tex]

That means :

[tex] \rightarrow \: L.H.S = R.H.S[/tex]

  • Hence , Verified .

Therefore, our answer is valid .

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