Respuesta :

I assume your question was to simplify the following fraction ;

[tex]{:\implies \quad \sf \dfrac{4a+3}{5}-\dfrac{2a+3}{3}}[/tex]

Taking LCM will yield ;

[tex]{:\implies \quad \sf \dfrac{3(4a+3)-5(2a+3)}{15}}[/tex]

[tex]{:\implies \quad \sf \dfrac{12a+9-10a-15}{15}}[/tex]

[tex]{:\implies \quad \boxed{\bf \dfrac{2a-6}{15}}}[/tex]

This is the required answer