Respuesta :
The required equation f(10) = 13.52 mg remains.
We have given that ,
m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60
What is the fromula for he amount of a radioactive substance remaining after t years?
The amount of a radioactive substance remaining after t years is given by the function
[tex]f(t)=m(0.5)^{t/h}[/tex]............ (1),
where m = initial mass and h= half-life in years.
Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,
then from equation (1) we get,
[tex]f(10)=50(0.5)^{10/5.3}[/tex]
Therefore the required equation f(10) = 13.52 mg .
To learn more about the mass of radioactive substance visit:
https://brainly.com/question/25793075
Answer:
The required equation f(10) = 13.52 mg remains.
We have given that ,
m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60
What is the fromula for he amount of a radioactive substance remaining after t years?
The amount of a radioactive substance remaining after t years is given by the function
............ (1),
where m = initial mass and h= half-life in years.
Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,
then from equation (1) we get,
Therefore the required equation f(10) = 13.52 mg .
To learn more about the mass of radioactive substance visit:
brainly.com/question/25793075
