Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV
Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.
To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:
where
[tex]E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\ [/tex]
substituting the values:
[tex]E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV[/tex]
Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV
Learn more about ionization energy at: https://brainly.com/question/1445179
