The human resources manager at a company records the length, in hours, of one shift at work, X. He creates the probability distribution below. What is the probability that a worker chosen at random works at least 8 hours? A probability distribution has the number of hours on the x-axis and the probability on the y-axis. The probability of 6 hours is 0. 02; 7 hours is 0. 11; 8 hours is 0. 61; 9 hours is 0. 15; 10 hours is 0. 9. 0. 62 0. 78 0. 84 0. 96.

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astha8579 astha8579 · Answer 1 · 2022-04-06T15:09:44+02:00

The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.

Suppose the random variable in consideration be X, and it is discrete.

Then, the probability of X attaining at least 'a' is written as:

[tex]P(X \geq a)[/tex]

It is evaluated as:

[tex]P(X \geq a) = \sum_{\forall \: x_i \geq a} P(X = x_i)[/tex]

The probability distribution of X is:

x f(x) = P(X = x)

6 0.02
7 0.11

8 0.61

9 0.15

10 0.09

Worker working at least 8 hours means X attaining at least 8 as its values.

Thus, probability of a worker chosen at random working 8 hours is

P(X ≥ 8) = P(X = 8) + P(X = 9) +P(X = 10) = 0.85 ≈ 0.84 approx.

By the way, this probability distribution seems incorrect because sum of probabilities doesn't equal to 1.

The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.

Learn more about probability distributions here:

https://brainly.com/question/14882721