A geometric sequence has a common ratio.
The formula for the nth term is
[tex]\sf{a_n =ar^{n-1} }[/tex]
where,
Given -
To find -
Solution -
A.T.Q, a = 2 and r = -2
[tex]\rightarrow\sf{a_{12} =2(-2)^{12-1} }[/tex]
[tex]\rightarrow\sf{a_{12 }=2(-2)^{11} }[/tex]
[tex]\rightarrow\sf{a_{12} =2×(-2048) }[/tex]
[tex]\rightarrow\bf{a_{12 }=-4096 }[/tex]
Hence, the 12th term is -4096.