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What current is required in the windings of a long solenoid that has 1580 turns uniformly distributed over a length of 0.44 m in order to produce a magnetic field of magnitude 0.000394 T at the center of the solenoid

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onyebuchinnaji

The current required in the windings of the given long solenoid that has 1580 turns uniformly distributed over the length of the solenoid is 1.98 A.

Magnetic field at the center of a solenoid

The magnetic field at the center of a solenoid is given by the following formula,

B = μ₀nI

where;

  • μ₀ is permeability of free space
  • n is number of turns
  • I is current in the solenoid

Current in the solenoid

I = B/μ₀n

I = (0.00394) / (4π x 10⁻⁷ x 1580)

I = 1.98 A

Thus, the current required in the windings of the given long solenoid is 1.98 A.

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