Answer:
[tex]\boxed{\sf{D. \quad 10a+5b}}[/tex]
Step-by-step explanation:
Use a distributive property.
Distributive property:
[tex]\Longrightarrow: \sf{A(B+C)=AB+AC}[/tex]
⇒ 5(a+a+b)
⇒ a+a=2a
Rewrite the problem down.
[tex]\Longrightarrow: \sf{5(2a+b)}[/tex]
Multiply should be expanded.
⇒ 5*2a=10a
⇒ 5*b=5b
Rewrite the problem.
⇒ = 10a+5b
- Therefore, the final answer is 10a+5b.
I hope this helps you! Let me know if my answer is wrong or not.
