The mass of NaOH that is necessary to neutralize 8.90 mol of HCl is 356 grams.
Mass of any substance will be calculated from moles by using the below equation as:
n = W/M, where
W = required mass
M = molar mass
Neutralization reaction will be:
NaOH + HCl → NaCl + H₂O
From the stoichiometry it is clear that 1 mole of NaOH is required to neutralize 1 mole of HCl, so that 8.90 moles of NaOH is needed.
Mass of 8.9 moles of NaOH = (8.9mol)(40g/mol) = 356g
Hence required mass of NaOH is 356 grams.
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