The doubling of the capacitance and the reduction of the voltage to half, the energy of the capacitor is reduced to half.
The capacitance is given as the storage of charge per unit voltage. It can be given as:
[tex]\rm C=\dfrac{Q}{V}[/tex]
The energy stored in the capacitor is given as :
[tex]\rm E=0.5\;CV^2[/tex]
The doubling of capacitance to 2C and reducing the voltage to 0.5V, the new energy is given as:
[tex]\rm E^n=0.5\;\times\;2C\;\times\;(0.5V)^2\\E^n=0.25\;CV^2\\E^n=0.5E[/tex]
Thus, with the doubling of the capacitance and the reduction of the voltage to half, the energy of the capacitor is reduced to half.
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