The value of maximum voltage, when the capacitor can withstand a peak voltage of 670 v is 47.6 volts.
Resonance frequency is the natural frequency of an particle or object. At this frequency, the object tries to vibrate at higher amplitude. It can be calculated with the following formula:
[tex]f=\dfrac{1}{2\pi LC}[/tex]
Here, L is the induction and C is the capacitance.
Let for an L-R-C circuit, the value of resistance is 400 ohm, induction is 0.380 Haney and capacitance is 1.20×10⁻² μF.
Put the values in above formula,
[tex]f=\dfrac{1}{2\pi(0.380)(1.20\times10^{-8})}\\f=2356.8\rm\; Hz[/tex]
The capacitor can withstand a peak voltage of 670 v. Use the following formula to find the value of current as,
[tex]I=2\pi fC\times Vc\\I=2\pi (2356.8)(1.20\times10^{-8})\times 670\\I=0.119\rm\; A[/tex]
The value of resistance is 400 ohms. Thus, the voltage is,
[tex]V=IR\\V=(0.119)(400)\\V=47.6\rm\; V[/tex]
Thus, the value of maximum voltage, when the capacitor can withstand a peak voltage of 670 v is 47.6 volts.
Learn more about the resonance frequency here:
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