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A diffraction-limited laser of length L and aperture diameter 0.50 cm generates light of wavelength 700nm . If the beam is directed at the surface and the radius of the illuminated area on the surface is approximately 45cm, how far away is the surface

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onyebuchinnaji

The distance of the surface illuminated by the light of the given wavelength is 5,269.32 m.

Distance of the surface

The distance of the surface illuminated by the light of the given wavelength is calculated as follows;

D = (rd)/(0.61λ)

where;

  • r is the radius of the illuminated area = 45 cm = 0.45 m
  • d is the diameter of the diameter = 0.5 cm = 0.005 m
  • λ is wavelength = 700 nm = 700 x 10⁻⁹ m

D = (0.45 x 0.005) / (0.61 x 700 x 10⁻⁹)

D = 5,269.32 m

Thus, the distance of the surface illuminated by the light of the given wavelength is 5,269.32 m.

Learn more about wavelength here: https://brainly.com/question/10728818

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