Respuesta :
Use the equation vf = vi + at to determine the acceleration:
54 = 32 + (a)(8)
22 = 8a
a = 2.75 km/h/s
B
54 = 32 + (a)(8)
22 = 8a
a = 2.75 km/h/s
B
Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
Initial velocity, [tex]v_{i}[/tex] = 32 km/hr, Final velocity, [tex]v_{f}[/tex] = 54 km/h
Time (t) = 8.0 seconds.
Calculate the acceleration, using the formula as follows.
[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + a × t
54 km/hr = 32 km/hr + a × 8 sec
(54 - 32) km/hr = a × 8 sec
22 km/hr = a × 8 sec
or, a = [tex]\frac{22 km/hr}{8 sec}[/tex]
= 2.75 km/hr/sec
= 2.8 km/hr/sec (approx)
Thus, we can conclude that acceleration of the car is 2.8 km/hr/sec (approx).