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If a car changes its velocity from 32 km/hr to 54 km/hr in 8.0 seconds, what is its acceleration?

216 km/hr/sec
2.8 km/hr/sec
-216 km/hr/sec
-2.8 km/hr/sec

Respuesta :

Use the equation vf = vi + at to determine the acceleration: 

54 = 32 + (a)(8) 
22 = 8a 
a = 2.75 km/h/s 

B

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

Initial velocity, [tex]v_{i}[/tex] = 32 km/hr,  Final velocity, [tex]v_{f}[/tex] = 54 km/h

Time (t) = 8.0 seconds.

Calculate the acceleration, using the formula as follows.

           [tex]v_{f}[/tex] = [tex]v_{i}[/tex] + a × t

               54 km/hr = 32 km/hr + a × 8 sec

                   (54 - 32) km/hr = a × 8 sec

                      22 km/hr = a × 8 sec

or,                      a = [tex]\frac{22 km/hr}{8 sec}[/tex]

                             = 2.75 km/hr/sec

                             = 2.8 km/hr/sec (approx)

Thus, we can conclude that acceleration of the car is 2.8 km/hr/sec (approx).