The answers to the given question are as follows:-
1. Cos(∠mA) = [tex]\dfrac{3}{5}[/tex]
2. Sin(∠mA) = [tex]\dfrac{\sqrt{20}}{\sqrt{35}}[/tex]
3. Tan(∠mB) = [tex]\dfrac{b}{a}[/tex]
Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.
The angles will be calculated by using trigonometric identities.
1. For the first triangle:-
Cos∠mA = [tex]\rm \dfrac{Base}{Hypotenuse}[/tex]
We can see in the first triangle base is 3 and the hypotenuse is 5.
Cos∠mA = [tex]\dfrac{3}{5}[/tex]
2. For the second triangle:-
Sin∠mA = [tex]\rm \dfrac{Perpendicualr }{Hypotenuse}[/tex]
We can see in the first triangle Perpendicular is √20 and the hypotenuse is √35.
Sin∠mA = [tex]\dfrac{\sqrt{20}}{\sqrt{35}}[/tex]
3. For the third triangle:-
Tan∠mB = [tex]\rm \dfrac{Perpendicualr }{Base}[/tex]
We can see in the first triangle Perpendicular is b and the Base is a.
Tan∠mA = [tex]\dfrac{b}{a}[/tex]
Therefore answers to the given question are as follows:-1. Cos(∠mA) = [tex]\dfrac{3}{5}[/tex]2. Sin(∠mA) = [tex]\dfrac{\sqrt{20}}{\sqrt{35}}[/tex] and 3. Tan(∠mB) = [tex]\dfrac{b}{a}[/tex]
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