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Grayson measured a line to be 10.9 inches long. If the actual length of the line is 13.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

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The percent error of the measurement, to the nearest tenth of a percent is 18.6%

Calculating percent error

The formula for calculating the percent error is expressed as:

%error = actual - measure/actual * 100

Given the following

actual length = 13.4 in

Measured =10.9in

Substitute

%error = 13.4-10.9/13.4 * 100
%error = 2.5/13.4 * 100
%error = 18.65%

Hence the percent error of the measurement, to the nearest tenth of a percent is 18.6%

Learn more on percent error here; https://brainly.com/question/1600371

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