Hi there!
We can use the following relationship between the Potential Difference and the Electric field:
[tex]V = E d[/tex]
V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)
We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]
Plug in the given values.
[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]
