Considering the given discrete probability distribution, it is found that [tex]P(2 < X \leq 4) = 0.14[/tex].
It give the probability of each outcome, and each outcome is represented by a countable number.
The desired probability is:
[tex]P(2 < X \leq 4) = P(X = 3) + P(X = 4)[/tex]
As there is an open interval at X = 2, it does not enter the calculation. The values are:
Hence:
[tex]P(2 < X \leq 4) = P(X = 3) + P(X = 4) = 0.1 + 0.04 = 0.14[/tex]
More can be learned about a discrete probability distribution at https://brainly.com/question/24802582
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