The solution of x in -6 + 3x - 9x^2 = -16 is [tex]x = \frac{3 \pm \sqrt{369}}{18}[/tex]
How to solve the equation?
The equation is given as:
-6 + 3x - 9x^2 = -16
Add 16 to both sides
10 + 3x - 9x^2 = 0
Rewrite as:
9x^2 - 3x - 10 = 0
Solve for x using the quadratic formula
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
So, we have:
[tex]x = \frac{3 \pm \sqrt{(-3)^2 - 4 * 9 * -10}}{2 * 9}[/tex]
Evaluate
[tex]x = \frac{3 \pm \sqrt{369}}{18}[/tex]
Hence, the solution of x in -6 + 3x - 9x^2 = -16 is [tex]x = \frac{3 \pm \sqrt{369}}{18}[/tex]
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