Answer:
[tex]x=-2\\[/tex]
Step-by-step explanation:
[tex]8^x=\frac{1}{64}\\xlog8=log\frac{1}{64}\\x=\frac{log\frac{1}{64}}{\log8}\\x=-2[/tex]
First we write the equation given
Next we take the log of both sides. This turns [tex]x[/tex] into a normal term instead of an exponent, but turns [tex]8[/tex] and [tex]64[/tex] into the log version of themselves.
Next we can divide both sides by [tex]log8[/tex] to isolate [tex]x[/tex].
This gives us our answer of [tex]\boxed{-2}[/tex]
