Respuesta :
1.
(x - 3)² + (y + 1)² = 10²
2.
2x² + 2y² + 4x - 8y - 6 = 0
x² + y² + 2x - 4y - 3 = 0
x² + 2x + 1 - 1 + y² - 4y + 4 - 4 - 3 = 0
Or x² + 2x + 1 is (x + 1)² and y² - 4y + 4 is (y - 2)²
Then (x + 1)² + (y - 2)² - 8 = 0
(x + 1)² + (y - 2)² = 8
Or 8 = (2 * sqrt(2) )²
The center is I ( -1 , 2 ) and the radius is 2 * sqrt(2)
3.
It is like a circle and the furthest points are those who verify the equation of the circle (x + 5)² + (y - 2)² = 12²
I hope i helped
(x - 3)² + (y + 1)² = 10²
2.
2x² + 2y² + 4x - 8y - 6 = 0
x² + y² + 2x - 4y - 3 = 0
x² + 2x + 1 - 1 + y² - 4y + 4 - 4 - 3 = 0
Or x² + 2x + 1 is (x + 1)² and y² - 4y + 4 is (y - 2)²
Then (x + 1)² + (y - 2)² - 8 = 0
(x + 1)² + (y - 2)² = 8
Or 8 = (2 * sqrt(2) )²
The center is I ( -1 , 2 ) and the radius is 2 * sqrt(2)
3.
It is like a circle and the furthest points are those who verify the equation of the circle (x + 5)² + (y - 2)² = 12²
I hope i helped