Well, to solve for x, you have to isolate it. I will show how to solve it, step-by-step below:
2x+3y=12
2x+3y-3y=12-3y
2x=-3y+12 ...divide both sides by 2
x=-3/2y+6
Now, to completely solve for x, you need to find what y is equal to. But to solve for y, you have to "get rid" of the x. You can use "-3/2y+6" in place of the x.
2(-3/2y+6)+3y=12
-6/2y+12+3y=12 ...simplify
-3y+12+3y=12 ...move the 12 to the other side
-3y+12-12+3y=12-12
-3y+3y=0 ...add like things
0=0
...oh. There is no solution...
Let me try doing y first...
2x+3y=12
3y=-2x+12
y=-2/3x+4
2x+3(-2/3x+4)=12
2x-6/3x+12=12
2x-2x=0
0=0
...yo...what is going on... are you sure you gave us the right numbers... no typos?
