Answer:
[tex]Mass_{NH_3}= 42.5775\ g[/tex]
Explanation:
Moles of [tex]N_2[/tex]:-
Mass = 35.00 g
Molar mass of [tex]N_2[/tex] = 28.014 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{35.00\ g}{28.014\ g/mol}[/tex]
[tex]Moles_{N_2}= 1.25\ mol[/tex]
According to the reaction:-
[tex]N_2_{(g)} + 3H_2_{(g)}\rightarrow 2NH_3_{(g)}[/tex]
1 mole of [tex]N_2[/tex] on reaction forms 2 moles of [tex]NH_3[/tex]
1.25 mole of [tex]N_2[/tex] on reaction forms 2*1.25 moles of [tex]NH_3[/tex]
Moles of [tex]NH_3[/tex] = 2.5 moles
Molar mass of [tex]NH_3[/tex] = 17.031 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]2.5\ mol= \frac{Mass}{17.031\ g/mol}[/tex]
[tex]Mass_{NH_3}= 42.5775\ g[/tex]
