The combustion of lauric acid is shown as CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)
In a combustion reaction, a substance is burnt in oxygen. If the substance is an organic compound a the case is here, the products are carbon dioxide and hydrogen.
No the equation of the combustion of lauric acid is shown as;
CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)
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