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If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KCI in the resulting solution?

If 447 g of KCI MM 7455 gmol are added to a 5000 mL volumetric flask and water is added to fill the flask what is the concentration of KCI in the resulting solu class=

Respuesta :

1.199 M is the concentration of KCI in the resulting solution.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

Learn more about moles here:

https://brainly.com/question/8455949

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