[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: x² + y² = 64[/tex]
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[tex] \large \tt Solution \: : [/tex]
Standard equation of circle is :
[tex]\qquad \tt \rightarrow \: (x - h) {}^{2} + (y - k) {}^{2} = {r}^{2} [/tex]
- [tex] \textsf{h = x - coordinate of centre of circle} [/tex]
- [tex] \textsf{k = y - coordinate of centre of circle} [/tex]
- [tex] \textsf{r = radius= 8} [/tex]
Since the circle is centered at origin, h = k = 0
[tex]\qquad \tt \rightarrow \: (x - 0) {}^{2} + (y - 0) {}^{2} = {8}^{2} [/tex]
[tex]\qquad \tt \rightarrow \: {x}^{2} + {y}^{2} = 64 [/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
