How many individual Ni atoms are contained in 1.25 grams of Ni? (Input your answer with scientific notation using "e-notation" and report your answer to two places past the decimal point.

We have a Nickel(Ni) atom . The atomic number of Ni is 28 .It is a silvery-white metal with a slight golden tinge. Ni belongs to the transitional metal series.

The electronic configuration of Ni = Ar4d⁸35²

Nickel is slowly oxidized by air at room temperature.

Nickel is a ferromagnetic element at approximately room temperature.

To answer the problem , we first need to divide by the molar mass of Ni to get the moles of Ni. And then we will multiply by Avogadro's number to find the number of Ni atoms.

Molar mass of Ni = 58.7gm

Given mass of Ni = 1.25gm

Avogadro’s No. = 6.022 × 10²³ atom/mole

Moles of Ni = Given mass/Molecular mass

= 1.25/58.7 = 0.0213

Moles of Ni = 0.0213

Now ,

Number of Ni atom = Avogadro’s number × Moles

So that,

No. of Ni atom = 6.022 × 10²³× 0.0213

= 0.128 ×10²³ atoms

= 1.28 × 10²² atoms

= 1.28e22

So there are 1.28 × 10²² individual Ni atoms are contained in 1.25 grams of Ni.

Learn more about the moles and molecular mass here:

https://brainly.com/question/27989722

#SPJ10