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A 5.00 g sample of hydrated sodium tetraborate, Na2B4O7 x nH2O is heated to drive off the water. After heating, 2.64 g of anhydrous Na2B4O7 reasons. What is the value of "n" in the hydrate formula

A 500 g sample of hydrated sodium tetraborate Na2B4O7 x nH2O is heated to drive off the water After heating 264 g of anhydrous Na2B4O7 reasons What is the value class=

Respuesta :

The value of ''n" in the hydrate formula is 10

Moles of anhydrous sodium tetraborate:

Mass of anhydrous NA2B4O7 = 2.64g

Molar mass of NA2B4O7 = 201.224 g/mol

Number of Moles of anhydrous NA2B4O7 = Mass of NA2B4O7 / Molar mass of NA2B4O7

                                                     = 2.64 / 201.224

                                                     = 0.0131 mol

Mass of water in 5.00g of NA2B4O7 = 5.00 - 2.64

                                                              = 2.36 g

Moles of water = 2.36 / 18.015

                          = 0.1307 mol

The whole number ratio = moles of water / moles of anhydrous sodium tetra borate

                                           = 0.1307 / 0.0131

The whole number ratio = 10

Hence the value of n in the hydrate formula is 10.

NA2B4O7. 10H2O

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